You can
put this solution on YOUR website!First set variables for James and Eric. Since James is 3 times the age of Eric, and 5 years ago James was 4 times the age of Eric, you would set up two equations. Let's say that Eric is e. Then your equations would be

and

. You can use the first equation

and plug in that value for james in the second equation. Then it becomes

. Then distribute on the right side

. Add five to both sides and get

. Then subtract 4e from both sides and get

. cancel out the negatives and you are left with

.
Eric=e and James=3e. Plug in 15 for e and you get Eric=15 and James=45.
To check, subtract 5 from each and get 10 and 40. Since 40 is 10(4), then our ages are correct. Eric=15 and James=45.