SOLUTION: Find three consecutive numbers such that 3 times the first is equal to 8 more than the sum of the other two.

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Question 14700: Find three consecutive numbers such that 3 times the first is equal to 8 more than the sum of the other two.
Answer by Alwayscheerful(414) About Me  (Show Source):
You can put this solution on YOUR website!
When you first read this, you probably thought that you needed three variables correct? Well, in fact, you only need 1!
They should be:
N, N+1, and N+2
Then you can just translate the word problem into a math equation
3%28N%29=8%2B%28%28N%2B1%29%2B%28N%2B2%29%29
Then you can just simplify and solve.
3N=8%2B2N%2B3
N=-5
That means the three numbers are:
-5,-4,-3
Hope this helps!