SOLUTION: i need solution. In a two digit number the digit at ten place is twice the digit at unit place.on interchanging the digits the number is reduced by 18. find the number.

Question 141369This question is from textbook Prentice hall algebra 1
: i need solution.
In a two digit number the digit at ten place is twice the digit at unit place.on interchanging the digits the number is reduced by 18. find the number. This question is from textbook Prentice hall algebra 1

Found 2 solutions by ptaylor, talwar.raveena1990@gmail.com:
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
Let x=the 10's digit of the original number
And let y= the unit's digit of the original number
The original number is 10x+y; if the digits are reversed, the new number would be 10y+x
Now we are told that:
x=2y------------------------------eq1
and
10x+y=10y+x+36-----------------------eq2
substitute x=2y from eq1 into eq2
10*2y+y=10y+2y+36 simplify
21y=12y+36 subtract 12y from each side
21y-12y=12y-12y+36 collect like terms
9y=36 divide each side by 9
y=4---------------------------the unit's digit
substitute y=4 into eq1
x=2*4=8--------------------------the 10's digit
So, the number is 84
CK
8=2*4
8=8
and
48+36=84
84=84

Hope this helps---ptaylor
Answer by talwar.raveena1990@gmail.com(1) (Show Source): You can put this solution on YOUR website!

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