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Jim is three times as old as his son. In 10 years, Jim will be twice as old as his
son. What are their current ages?
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The son's age = x years.
The Jim's age= 3x years.
In 10 years
2(x+10) = 3x+10
Simplify and find x
2x + 20 = 3x + 10
20 - 10 = 3x - 2x
10 = x.
ANSWER. The son is 10 years old. Jim is 3*10 = 30 years old.
Solved.
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For introductory age problems, look into the lessons
- Age problems and their solutions
- HOW TO algebreze and to solve age problems?
- A fresh formulation of a traditional age problem
in this site.
Learn the subject from there.