SOLUTION: Andrew can paint the neighbors house 5 times as fast as Bailey. They year Andrew and Bailey worked together it took them 9 days. How long would it take each to paint the house?

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Question 1200416: Andrew can paint the neighbors house 5 times as fast as Bailey. They year Andrew and Bailey worked together it took them 9 days. How long would it take each to paint the house?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
duplicate
already answered

Answer by ikleyn(52814)   (Show Source): You can put this solution on YOUR website!
.

Was solved many years ago at this forum under this link

https://www.algebra.com/algebra/homework/Rate-of-work-word-problems/Rate-of-work-word-problems.faq.question.653878.html

https://www.algebra.com/algebra/homework/Rate-of-work-word-problems/Rate-of-work-word-problems.faq.question.653878.html


        Alternative to that algebraic solutions is THIS mental solution below:


When they will complete the job, Andrew will complete  5/6  of the job, while Bailey will complete  1/6  of the job.


Thus Bailey makes 1/6 of the job in 9 days.

Hence, Bailey can make the entire job in  6*9 - 54 days working alone.


It implies that Andrew can complete the job in  54/5 = 10   days, working alone.



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