SOLUTION: A positive real number is 2 less than another. If the sum of the squares of the two numbers is 6, find the numbers.

Question 1199231: A positive real number is 2 less than another. If the sum of the squares of the two numbers is 6, find the numbers.
Answer by ikleyn(52790) (Show Source): You can put this solution on YOUR website!
.


Let x be the smaller positive real number.


Then the larger number is (x+2), and the problem leads to equation

    x^2 + (x+2)^2 = 6    (the sum of squares is 6).


Simplify and find x

    x^2 + (x^2 + 4x + 4) = 6

    2x^2 + 4x -2 = 0

     x^2 + 2x - 1 = 0


Use the quadratic formula

      =  =  = .


ANSWER.  The numbers are  x =   (the positive root) and .

Solved.

RELATED QUESTIONS
A positive real number is 6 less than another. If the sum of the squares of the two... (answered by ikleyn)

A positive real number is 6 less than another. If the sum of the squares of the two... (answered by jorel1380)

A positive real number is 6 less than another. If the sum of the squares of the two... (answered by Alan3354,ikleyn)

a positive real number is 4 less than another. If the sum of the squares of the two... (answered by josgarithmetic,ikleyn)

A positive real number is 4 more than another. If the sum of the squares of the two... (answered by jorel555)

A positive real number is 4 more than another. If the sum of the squares of the two... (answered by jorel1380)

A positive real number is 4 more than another. If the sum of the squares of the two... (answered by math_helper)

A positive real number is 4 more than another. If the sum of the squares of the two... (answered by MathLover1)

One number is 6 less than another number. If the sum of the two numbers is 150, find the... (answered by stanbon)