SOLUTION: The product of two consecutive odd integers is 1 less than 5 times their sum. Find the two integers. Answer in the form of paired points with the lowest of the two integers

Question 1194141: The product of two consecutive odd integers is
1
less than
5
times their sum. Find the two integers. Answer in the form of paired points with the lowest of the two integers first.

Found 2 solutions by josgarithmetic, Alan3354:
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
----------------------
The product of two consecutive odd integers is
1
less than
5
times their sum. Find the two integers. Answer in the form of paired points with the lowest of the two integers first.
-----------------------

=======================================================================
The product of two consecutive odd integers is 1 less than
5 times their sum. Find the two integers.
=======================================================================

Integers n and n+2

-----------and you can now find the two possible pair of integers.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The product of two consecutive odd integers is 1 less than 5 times their sum.
Find the two integers.
------------
n*(n+2) + 1 = 5(n + n+2)
n^2 + 2n + 1 = 10n + 10
n^2 - 8n - 9 = 0
(n-9)*(n+1) = 0
n = 9
---> n & 11
=============
n = -1
---> -1 & +1
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