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The members of a mathematics club agreed to contribute equally to
provide a fund of P240. If there had been 3 more members each would
have paid P4 less than the original agreement. How many members
were present in the club?
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Let n be the number of members.
Then each contributes pesos.
Had the number of members be (n+3), each would contribute pesos.
The problem says
- = 4 pesos. (1)
Cancel the factor 4 in both sides
- = 1. (2)
From this point, you may reduce the problem to the quadratic equation, which can be solved by factoring.
Alternatively, you can easily GUESS the solution MENTALLY : n= 12.
CHECK. - = - = 5 - 4 = 1. ! Equation (2) is held !
ANSWER. There are 12 members in the club.
Solved.