.
Joe can paint a room in 6 hours less time than Jay. If they can paint the
room in 4 hours working together, how long would it take each to paint
the room working alone
~~~~~~~~~~~~~~~
Let x be the time for Joe to complete the job alone, in hours;
then the time for Jay is (x+6) hours.
In one hour, Joe makes part of the entire job, working alone;
Jay makes part of the entire job, working alone.
Working together, they make of the job in one hour.
It gives an equation
+ = . (1)
It is your basic equation. As soon as you get it, the setup is done.
To solve the equation, multiply both sides by 4x*(x+6) and simplfy. You will get
4(x+6) + 4x = x^2 + 6x
x^2 - 2x - 24 = 0.
Factor left side
(x-6)*(x+4) = 0.
Of two roots, x= 6 and x= 4, only positive x= 6 is meaningful.
It gives the ANSWER to the problem:
Joe con make the entire work in 6 hours, working alone; Jay can do it in 6+6 = 12 hours.
CHECK. + = = = = . ! Correct. Equation (1) is held !
Solved.
------------------
It is a standard and typical joint work problem.
There is a wide variety of similar solved joint-work problems with detailed explanations in this site. See the lesson
- Using quadratic equations to solve word problems on joint work
Read it and get be trained in solving joint-work problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this textbook under the topic
"Rate of work and joint work problems" of the section "Word problems".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.