SOLUTION: A golfer hits a ball from an elevated tee with an upward velocity of 160ft/s. It’s height h in feet after t second is given by the function h = -16t2 + 160t + 18.

SOLUTION: A golfer hits a ball from an elevated tee with an upward velocity of 160ft/s. It’s height h in feet after t second is given by the function h = -16t2 + 160t + 18.

Algebra.Com

Question 1177607: A golfer hits a ball from an elevated tee with an upward velocity of 160ft/s. It’s height h in feet after t second is given by the function h = -16t2 + 160t + 18.

Answer by ikleyn(52909) (Show Source): You can put this solution on YOUR website!
.

Thanks for letting us know.

We were so suffered here without knowing this info . . .

RELATED QUESTIONS
a golfer strikes a golf ball with an initial upward velocity of 80 feet per second the... (answered by ewatrrr,MathLover1,ikleyn,Alan3354)

Please help me solve this equation: A ball is thrown upward with an initial velocity... (answered by KnightOwlTutor)

Hi, please help me answer this problem: The height in feet of a golf ball hit from an... (answered by scott8148)

A ball is thrown from an initial height of 4 feet with an initial upward velocity of (answered by Boreal)

A ball is thrown from an initial height of 4 feet with an initial upward velocity of 32... (answered by Alan3354)

A ball is thrown from an initial height of 6 feet with an initial upward velocity of 33 (answered by richwmiller)

please help A ball is thrown from an initial height of 5 feet with an initial upward... (answered by ikleyn)

Word Problem Help A ball is thrown from an initial height of 4 feet with an initial... (answered by MathLover1)

In physics, one learns that the height of an object thrown upward from an initial height... (answered by Boreal)