# SOLUTION: When the digits of a two-digit number are reversed, the new number is 9 more than the original number, and the sum of the digits of the original number is 11. What is the original

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 Question 117720: When the digits of a two-digit number are reversed, the new number is 9 more than the original number, and the sum of the digits of the original number is 11. What is the original number?Answer by stanbon(57203)   (Show Source): You can put this solution on YOUR website!When the digits of a two-digit number are reversed, the new number is 9 more than the original number, and the sum of the digits of the original number is 11. What is the original number? --------------- Let the original number be 10t+u where t is the tens digit and u is the units digit. ----------------- When reversed the number would be 10u+t ------------------ EQUATION: 10u+t=10t+u+9 t+u=11 --------- Rearrange to get: 9u-9t=9 u-t=1 u+t=11 ---------- Add the last two to solve for "u": 2u = 12 u = 6 Substitute to solve for "t": 6+t=11 t = 5 ----------- Original Number: 56 ======================== Cheers, Stan H.