SOLUTION: Find two numbers such that one of them exceeds the other by 18 and their sum is 92.

Question 1168946: Find two numbers such that one of them exceeds the other by 18 and their sum is 92.

Found 2 solutions by Theo, MathTherapy:
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
let the two numbers be x and y.
x = y + 18
x + y = 92
replace x with y + 18 to get:
y + 18 + y = 92
combine like terms to get:
2y + 18 = 92
subtract 18 from both sides of the equation to get:
2y = 74
solve for y to get:
y = 74/2 = 37
x = y + 18 = 55
x + y = 92 becomes 37 + 55 = 92 which becomes 92 = 92 which confirms the solution is correct.
the two numbers are 37 and 55.

Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

Find two numbers such that one of them exceeds the other by 18 and their sum is 92.

Let the smaller number be S
Then larger is: S + 18
We then get: S + S + 18 = 92
2S = 74
Smaller number, or
You should now be able to find the larger number!
RELATED QUESTIONS
find two numbers such that one of them exceeds the other by 18 and their sum is... (answered by Maths68,ssm@123)
The sum of two numbers is 92, and one exceeds the other by 40. What are the... (answered by flame8855)
Of two numbers, one exceeds the other by 32. Their sum is 46. Find the... (answered by jojo14344)
Of two numbers , one exceeds the other by 32. their sum is 46 . find the... (answered by rfer)
find two numbers such that the sum of twice the first and the second is 92, and four... (answered by flame8855)
One of two numbers exceeds the other by 10, and their sum is 126. What are the... (answered by flame8855)
find two numbers such that the sum of twice the first and thrice the second is 92 and... (answered by ankor@dixie-net.com)
Find two numbers, one of which is double the other, if the square of their sum exceeds... (answered by Alan3354)
The sum of two numbers is five times their difference. If one number exceeds the other... (answered by stanbon,ssm@123)