SOLUTION: 1. Wilson and Matthew own a small business. Wilson, working alone can complete a job in 5 hours. Matthew can complete the same job in 6 hours. How long would it take them to comple
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Question 1167915: 1. Wilson and Matthew own a small business. Wilson, working alone can complete a job in 5 hours. Matthew can complete the same job in 6 hours. How long would it take them to complete the job working together?
2. margarette and cypress were asked to clean the backyard. Margarette clean the backyard in x minutes while cypress is slower by 10 minutes compared to margarette.
A. What part of the job can margarette finish in 1 minute?
B. What part of the job can cypress finish in 1 minute?
C. Margarette and cypress can finish cleaning the tank together within y minute. How will you represent algebraically, in simplest form, the job done by the two if they worked together?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
1. Wilson and Matthew own a small business. Wilson, working alone can complete a job in 5 hours.
Matthew can complete the same job in 6 hours.
How long would it take them to complete the job working together?
let t = time required when working together
let t = the completed job
each will do a fraction of the job, the two fractions add up to 1
+ = 1
multiply the eq by 30, cancel the denominators
6t = 5t = 30
11t = 30
t = 30/11
t = 2.73 hrs or 2 + .73*60 = 2 hrs 44 min working together
:
2. margarette and cypress were asked to clean the backyard.
Margarette clean the backyard in x minutes while cypress is slower by 10 minutes compared to margarette.
x = M's time (in minutes)
then
(x+10) = C's time
A. What part of the job can margarette finish in 1 minute?
B. What part of the job can cypress finish in 1 minute?
C. Margarette and cypress can finish cleaning the tank together within y minute.
How will you represent algebraically, in simplest form, the job done by the two if they worked together?
let the completed job = 1
+ = 1
multiply eq by x(x+10), cancel the denominators
y(x+10) + yx = x(x+10)
yx + 10y + yx = x^2 + 10x
factor out y
y(x + 10 +x) = x^2 + 10x
y(2x+10) = x^2 + 10x
y =
:
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