SOLUTION: The sum of 2 consecutive integers is 41 less than four times the larger. Find the numbers.

Question 1164584: The sum of 2 consecutive integers is 41 less than four times the larger. Find the numbers.
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52790) (Show Source): You can put this solution on YOUR website!
.

A TWIN problem was solved under this link

https://www.algebra.com/algebra/homework/word/numbers/Numbers_Word_Problems.faq.question.1164581.html

https://www.algebra.com/algebra/homework/word/numbers/Numbers_Word_Problems.faq.question.1164581.html

Why don't you use it as a TEMPLATE and solve the given problem ON YOUR OWN to educate yourself ?

Isn't it a very good idea ?

Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
n-1 and n

-

19 and 20
RELATED QUESTIONS
The sum of three consecutive odd integers is 41 less than four times the largest. Find... (answered by stanbon)
the sum of two consecutive odd integers is 21 less than 3 times the larger number. Find... (answered by josgarithmetic)
The sum of two consecutive odd integers is 21 less than three times the larger integer.... (answered by ankor@dixie-net.com)
three times the sum of two consecutive integers is three less than two times the larger... (answered by mananth)
1.) The sum of two consecutive integers is 50 less than three times the larger integer.... (answered by solver91311)
the sum of two consecutive even integers is 16 less than three times the larger number.... (answered by macston)
the sum of two consecutive even integers is 16 less than three times the larger number.... (answered by macston)
The sum of four consecutive integers is 14 less than 5 times the smallest integer. Find... (answered by fractalier)