Instead of doing your problem, here is another one EXACTLY like yours
in every way for you to use as a model in doing yours:
How to find the number? The units digit of a two-digit number is five more
than the tens digit. The number is equal to three times the sum of the
digits. Find the number.(Hint:we can represent a two digit number as 10t+u.)
t = tens digit
u = units digit
10t+u = the two-digit number
t+u = sum of digits
The units digit of a two-digit number is five more than the tens digit.
units digit = tens digit + 5
u = t + 5
u = t + 5
The number is equal to three times the sum of the digits.
The number = 3 times sum of digits
10t+u = 3 ∙ (t+u)
10t + u = 3(t + u)
Find the number.
Substitute t + 5 for u in
10t + u = 3(t + u)
10t + t + 5 = 3(t + t + 5)
11t + 5 = 3(2t + 5)
11t + 5 = 6t + 15
5t = 10
t = 2
Substitute 2 for t in
u = t + 5
u = 2 + 5
u = 7
The tens (first) digit is 2 and the units (second) digit is 7.
So the number is 27.
Now do your problem the exact same way.
Edwin