SOLUTION: . A solid metal cube of side 6 inches is placed in a rectangular tank whose length, width, and height are 1, 2, and 3 feet. What is the volume, in cubic units, of water that the

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: . A solid metal cube of side 6 inches is placed in a rectangular tank whose length, width, and height are 1, 2, and 3 feet. What is the volume, in cubic units, of water that the       Log On

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Question 116140: . A solid metal cube of side 6 inches is placed in a rectangular tank whose length, width, and height are 1, 2, and 3 feet. What is the volume, in cubic units, of water that the tank can now hold?

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
This is how I interpret what the problem is asking you to find.
.
When empty, the tank can hold a maximum of 6 cubic feet of water. You find that volume by
multiplying the three dimensions of the tank ... 1 ft times 2 ft times 3 ft = 6 cu ft.
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When the tank is empty you put the metal cube in it. The question then is how many cubic feet
of water can you then put into the tank before the tank is full.
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Since the metal cube is 6 inches on a side, each side is 1%2F2 foot long. Therefore, the volume
of this cube is the product of %281%2F2%29%2A%281%2F2%29%2A%281%2F2%29+=+1%2F8 or 1/8 cubic ft
.
Once the cube is in the tank, water cannot occupy that 1/8 cubic ft of space. So the amount
of remaining space that water can occupy is the original 6 cubic feet less 1/8 cubic ft
which is 5 7/8 cubic feet or in decimal form 5.875 cubic feet.
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Hope this helps you to understand the problem and how you can work it.
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