SOLUTION: Solve: 1-2/m=8/m^2?
Algebra
.Com
Question 1159696
:
Solve: 1-2/m=8/m^2?
Found 4 solutions by
josgarithmetic, solver91311, MathLover1, MathTherapy
:
Answer by
josgarithmetic(39618)
(
Show Source
): You can
put this solution on YOUR website!
1-2/m=8/m^2
check:
yes.
--
?
check for -2,
yes this too.
Answer by
solver91311(24713)
(
Show Source
): You can
put this solution on YOUR website!
Add
to both sides.
Multiply both sides by
Solve the factorable quadratic in
John
My calculator said it, I believe it, that settles it
Answer by
MathLover1(20850)
(
Show Source
): You can
put this solution on YOUR website!
.....both sides multiply by
........factor
solutions:
if
->
if
->
Answer by
MathTherapy(10552)
(
Show Source
): You can
put this solution on YOUR website!
Solve: 1-2/m=8/m^2?
------ Multiplying by LCD, m
2
(m - 4)(m + 2) = 0
m - 4 = 0 OR m + 2 = 0
RELATED QUESTIONS
Please solve 1) 8/x+9=5/2x+(15/4) 2)...
(answered by
josgarithmetic
)
{{{ m^2 + m / (m-2) (m+1)...
(answered by
ikleyn
)
M<1=2x+2and m<2=4x-8 <1 and <2 are congruent solve for x
(answered by
stanbon
)
Please help me solve this equation: {{{ 1/(m^2-m) + 1/(m) = 5/(m^2-m) }}}
(answered by
stanbon
)
If m<4=122 what is m<8 m<5 m<2 m<1 m<6...
(answered by
ikleyn
)
m<1=...
(answered by
Edwin McCravy
)
solve for b then give the equation in slope-intercept form (1,3) and m=-2 (-6,7) and...
(answered by
checkley77
)
Solve for m....
(answered by
checkley77
)
Solve log4 (m+2)-log4 (m-5)=log4...
(answered by
ikleyn,josmiceli
)