SOLUTION: How many numbers of four different digits can be formed from the digits 1,2,3,4,5,6,7,8, and 9 if each number must consist of two odd and two even digits?

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Question 1157462: How many numbers of four different digits can be formed from the digits 1,2,3,4,5,6,7,8, and 9 if each number must consist of two odd and two even digits?
Answer by greenestamps(13203) About Me  (Show Source):
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Choose 2 of the 5 odd digits: C(5,2) = 10 ways

Choose 2 of the 4 even digits: C(4,2) = 6 ways

Arrange the 4 chosen digits to form a 4-digit number: 4!=24 ways

ANSWER: 10*6*24 = 1440