SOLUTION: Find three consecutive odd integers such that double the sum of the first two is equal to fifteen more than triple the third

Algebra.Com
Question 1154082: Find three consecutive odd integers such that double the sum of the first two is equal to fifteen more than triple the third
Found 2 solutions by mananth, MathTherapy:
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!

Let the three integers be n,n+1,n+2
double the sum of first two= 2(n+n+1)
15 more than 3(n+2)
2(n+n+1)=15+ +3(n+2)
4n+2 = 15+3n+6
n= 19
so you know the numbers

Answer by MathTherapy(10556)   (Show Source): You can put this solution on YOUR website!

Find three consecutive odd integers such that double the sum of the first two is equal to fifteen more than triple the third
The 1st number being 19 is NOT correct!
Correct answer: First number: 23
Now, can you find the rest?
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