SOLUTION: A courier who goes at the rate of 4.5mi./h is followed, after 6.0h, by another who goes at the of 5.5mi./h. In how many hours will the second overtake the first?, x=? 
Algebra.Com
Question 1152903:  A courier who goes at the rate of 4.5mi./h is followed, after 6.0h, by another who goes at the of 5.5mi./h. In how many hours will the second overtake the first?, x=?  
Answer by greenestamps(13209)   (Show Source): You can put this solution on YOUR website!
 
In 6 hours, the distance the first courier travels is 6(4.5) = 27 miles.
The difference in the rates of the two couriers is 1 mi/hr.
The time required to make up the distance of 27 miles at the rate of 1 mi/hr is 27/1 = 27 hours.
 
RELATED QUESTIONS
A courier who goes at the rate of  6.5 min/h is followed, after 4.0 h , by another who... (answered by josgarithmetic,ikleyn)
A courier who goes at the rate of 7.5 mi./h is followed, after 2.0 h, by another who goes  (answered by ikleyn)
A courier who goes at the rate of 7.5 mi./h is followed, after 2.0 h, by another who goes  (answered by ikleyn)
A courier who goes at the rate of 4.5mi./h is followed, after 6.0h, by another who goes... (answered by josgarithmetic)
Please help me solve this.
A courier who goes at the rate of 6.5 mi./h is followed,... (answered by josgarithmetic)
 A courier who travels at the rate of 6.5 mi/hour is followed, after 30 minutes, by... (answered by ikleyn)
find the rate at which a man walks if he walks 8^5mi in 4(10^3)... (answered by stanbon)
"A tortoise crawling at a rate of 0.1mi/h passes a resting hare. The hare wants to rest... (answered by MathTherapy)
In a walkathon to raise money for a charity, Elisa walked a certin distance at 5mi/h and... (answered by josmiceli)