SOLUTION: Find two consecutive odd integers such that the sum of their squares is 802.

Question 1148790: Find two consecutive odd integers such that the sum of their squares is 802.

Answer by ikleyn(52846) (Show Source): You can put this solution on YOUR website!
.

Let "x" be the EVEN integer number exactly between the two unknown consecutive unknown integer numbers.


Then the unknown odd integer numbers are (x-1) and (x+1),

and the problem says that


     +  = 802.

Then

     +  = 802

     + 2 = 802

     = 800

     = 800/2 = 400

    x = +/-  = +/- 20.


Thus, there are two pairs of consecutive integer numbers satisfying the condition.


One pair is (19,21),  The other pair is (-21,-19).    ANSWER

Solved.

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