SOLUTION: The sum of three consecutive integers is 18 more than 2 times the largest number.Find the three numbers.

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Question 1147875: The sum of three consecutive integers is 18 more than 2 times the largest number.Find the three numbers.
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
The sum of three consecutive integers is 18 more than 2 times the largest number.Find the three numbers.
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Use n-1, n & n+1 for the 3 integers.
The sum is 3n
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etc
Answer by ikleyn(52909)   (Show Source): You can put this solution on YOUR website!
.

If the three consecutive integer numbers are (n-1), n and (n+1),

then your equation is


    (n-1) + n + (n+1) = 2*(n+1) + 18,   or

     3n               = 2*(n+1) + 18,

     3n               = 2n + 20

     3n - 2n          = 20

      n               = 20,


so the three integer numbers are 19, 20 and 21.            ANSWER

You can check it on your own that my answer satisfies the condition.



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