.
It is typical and standard problem on mixture.
It intently includes many words and whole story to confuse the reader and distract his (or her) attention.
Its shortest formulation is THIS :
How much of pure antifreeze and how much of 40% antifreeze should be mixed
to make 4 liters of the 40% antifreeze.
Solution
Let x be the volume of the pure antifreeze.
Then the volume of the 40% antifreeze should be (4-x) liters.
The basic equation is
x + 0.4*(4-x) = 0.7*4
saying that the sum of antifreeze volumes in ingredients is equal to the volume of the antifreeze in the mixture.
From equation, express x and calculate
x = = 2 liters.
ANSWER. 2 liters of the 70% antifreeze should be mixed with 2 liters of the pure antifreeze.
Solved.
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There is a bunch of introductory lessons in this site, covering various types of mixture problems
- Mixture problems
- More Mixture problems
- Solving typical word problems on mixtures for solutions
- Word problems on mixtures for antifreeze solutions
- Word problems on mixtures for alloys
- Typical word problems on mixtures from the archive
Read them and become an expert in solution the mixture word problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Mixture problems".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.