SOLUTION: Sherlock made an elaborate code to remember the 10-digit combination to his locker. This is the code he came up with: A - K - B - J - C - H - D - G - E - F Each letter stand

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: Sherlock made an elaborate code to remember the 10-digit combination to his locker. This is the code he came up with: A - K - B - J - C - H - D - G - E - F Each letter stand      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1147211: Sherlock made an elaborate code to remember the 10-digit combination to his locker. This is the code he came up with:
A - K - B - J - C - H - D - G - E - F
Each letter stands for a different single digit number, from 0-9.
To find the combination, study the clues below to figure out what digit is represented by each letter. When two letters are written together without an operation symbol, they represent a tens digit and a ones digit.
D + D + D = F
H + H = B
G + B +E = F + A +C
J + A = CC
F x D = KG (x means multiplied by)
B / H = K (/ means divided by)
D x H = CK
A x H = KE
J / D = K
D H (this is fractions, D over J and H over B)
- = -
J B
What is the 10 digit combination to Sherlock's locker?

Found 2 solutions by MathLover1, greenestamps:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

H+%2B+H+=+2H+=+B, so H%2FB+=+1%2F2
Then D%2FJ+=+1%2F2, so J%2FD+=+2

Hence K+=+2.
We therefore also have a bunch of doubling pairs: 1-2, 2-4, 3-6, 4-8. But K=2, so J and D are either 3-6 or 4-8.
Note that J & D are one set, and H & B are the other distinct set.
Further, D and F are a tripled pair.
Note that F+=+3D, so+D = 1,2,3. But from above, D=3,4, so D+=+3.
Then J+=+6 and F+=+9. Further, HB must be the other double pair available, 4-8. Hence H+=+4 and B+=+8.
Now, F+%2A+D+=+9+%2A+3+=+27+=+KG, so G+=+7.
Since J+=+6 and J+%2B+A+=+CC, J%2BA+%3C+16 so CC+=+11 and C+=+1.
Further, A+=+5. Then A%2A+H+=+KE => 5+%2A+4+=+2E+=+20, so E+=+0.

solution: A+-+K+-+B+-+J+-+C+-+H+-+D+-+G+-+E+-+F is 5-2-8-6-1-4-3-7-0-9

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Given:
1. D + D + D = F
2. H + H = B
3. G + B +E = F + A +C
4, J + A = CC
5. F x D = KG
6. B / H = K
7. D x H = CK
8. A x H = KE
9. J / D = K
10. D/J = H/B

Analysis…

From 4, C is 1

From all the given information together, E and G are the only possible letters for 0.
If G is 0, then 5 tells us either D or F is 5; but 1 tells us neither D nor F can be 5.
So G is not 0; therefore E is 0.

Since E is 0, 8 tells us either A or H is 5.
But 10 tells us H can’t be 5.
So A is 5.

Then 4 tells us J is 6.

Then, since J is 6, 9 tells us D and K are, in some order, 2 and 3.
But D can’t be 2, because 1 would make F 6, but J is 6.
So D is 3; and so K is 2.

Then 1 tells us F is 9.

Then 5 tells us G is 7.

8 tells us H is 4.

6 tells us B is 8.

His code is

A - K - B - J - C - H - D - G - E - F = 5286143709