SOLUTION: find three consecutive integers such that the square of the largest is 23 less than the product of the smaller two. please solve!

SOLUTION: find three consecutive integers such that the square of the largest is 23 less than the product of the smaller two. please solve!

Algebra.Com

Question 1145277: find three consecutive integers such that the square of the largest is 23 less than the product of the smaller two. please solve!
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!

RELATED QUESTIONS
Find three consecutive integers such that the square of the largest is 22 more than the... (answered by josgarithmetic,ikleyn)

The product of the smaller two of three consecutive integers is equal to 23 plus the... (answered by ankor@dixie-net.com)

find the smallest of three consecutive positive integers such that the product of two... (answered by ad_alta)

find three consecutive integers such that the product of the two smaller inters is 2 more (answered by EMStelley)

find three consecutive integers such that the product of the two smaller inters is 2 more (answered by Earlsdon)

Quadratic word problem: Find three consecutive integers such that the product of the... (answered by robertb)

Find three consecutive integers such that the square of the sum of the smaller two is 144 (answered by josmiceli)

Find three consecutive integers such that the square of the sum of the smaller two is 297 (answered by mananth)

Find three consecutive integers such that the square of the sum of the smaller two is 105 (answered by josgarithmetic,ikleyn,MathTherapy)