SOLUTION: the positive integers are written in order starting with 1: 1-2-3-4-5-6-7-8-9-1-0-1-1-1-2-1-3-1-4-1-5-1-6-1-7-1-8-1-9-2-0-2-1-2-2-2-3-2-4-2-5-2-6-2-7-2-8. . . What digit is in

Question 1144185: the positive integers are written in order starting with 1:
1-2-3-4-5-6-7-8-9-1-0-1-1-1-2-1-3-1-4-1-5-1-6-1-7-1-8-1-9-2-0-2-1-2-2-2-3-2-4-2-5-2-6-2-7-2-8. . .
What digit is in the 5000th position?
A)-1
B)-2
C)-5
D)-6
Answer by ikleyn(52802) (Show Source): You can put this solution on YOUR website!
.


There are   9  one-digit  numbers from 1    to   9 inclusively :    9 digits, in all.


There are  90 two-digit   numbers from 10   to  99 inclusively :  180 digits, in all.


There are 900 three-digit numbers from 100  to 999 inclusively : 2700 digits, in all.



Thus, 9 + 180 + 2700 = 2889 places are just occupied by one-digit, two-digits and three-digits numbers.



Starting from the position 2890, the four-digit are placed, each occupies 4 position.



Between  5000-th position and 2890-th position, there are  about   =527.75, 

and more precisely, 527 four-digit numbers from 1000 to 1526, inclusively.


The next number is 1527, giving its third digit " 2 " at the 5000-th position.



ANSWER.  The digit " 2 " is at 5000-th position.

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