SOLUTION: A plumber cuts an 83 in.pipe into 2 pieces. The first piece is 7 in. less than 8 times as long as the second piece.

Algebra.Com
Question 1142159: A plumber cuts an 83 in.pipe into 2 pieces. The first piece is 7 in. less than 8 times as long as the second piece.
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52803)   (Show Source): You can put this solution on YOUR website!
.

Do you have a question ?

Which help do you need ?



Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
x, the second piece
8x-7, first piece

-----------The description.

Solve for x and evaluate 8x-7.

RELATED QUESTIONS

A 96 inch pipe is cut into 3 pieces. The second piece is seven inches shorter than the... (answered by checkley77)
A pipe is 48 inches long.Cut into three pieces so that the second piece is 1 inch less... (answered by edjones)
A 64 inch board is cut into 3 pieces. The second piece is three times as long as the... (answered by Nate)
Jane cuts a piece of rope into three pieces. The second piece is 7 times as long as the... (answered by josgarithmetic)
How do you figure out these kinds of problems. A 30 yd long pipe is cut into 3 pieces.... (answered by solver91311)
a 480m pipe is cut into three pieces the second piece is three times as long as the... (answered by lwsshak3)
I am needing help in setting up this equation: A 96 ft rope is cut into 4 pieces. The... (answered by ikleyn,VFBundy,solver91311,Theo,MathTherapy)
A 48 foot long piece of cable wire is to be cut into three pieces so that the second... (answered by advanced_Learner)
Question A twenty-foot piece of wire is cut into three pieces. The first piece is twice... (answered by jim_thompson5910)