SOLUTION: A newspaper carrier has $3.80 in change he has four more quarters than dimes but five as many nickels as quarters how many coins of each type does he have

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Question 1130998: A newspaper carrier has $3.80 in change he has four more quarters than dimes but five as many nickels as quarters how many coins of each type does he have
Answer by ikleyn(52915)   (Show Source): You can put this solution on YOUR website!
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A newspaper carrier has $3.80 in change he has four more quarters than dimes but five as many nickels as quarter.
How many coins of each type does he have
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Let Q be the number of quarters.

Then the number of dimes is (Q-4), and the number of nickels is 5Q.


The equation for the total is


    25Q + 10*(Q-4) + 5*(5Q) = 380     cents.


    25Q + 10Q - 40 +25Q = 380

    60Q = 380 + 40 = 420

    Q = 420/60 = 7.


Answer.  7 quarters,  5*7 = 35 nickels  and  7-4 = 3 dimes.


Check.   7*25 + 35*5 + 3*10 = 380 cents  total.   ! Correct !

Solved.


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