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Let x be the "ones" digit.
Then "tens" digit is (x+4) and "hundreds" digit is (((x+4)-7) = x-3.
Then the equation is
x + (x+4) + (x-3) = 16
3x +1 = 16 ====> 3x = 15 ====> x= 5.
Answer. The numbers is 295.
The lesson to learn from this solution :
This problem is for one unknown and one equation.
There is no any need to use three unknowns and three equations.