Let x be the "ones" digit. Then "tens" digit is (x+4) and "hundreds" digit is (((x+4)-7) = x-3. Then the equation is x + (x+4) + (x-3) = 16 3x +1 = 16 ====> 3x = 15 ====> x= 5. Answer. The numbers is 295.
This problem is for one unknown and one equation. There is no any need to use three unknowns and three equations.