SOLUTION: Three consecutive integers are such that the square of the third is 76 more thant the square of the second. Find the integers.

Question 111508: Three consecutive integers are such that the square of the third is 76
more thant the square of the second. Find the integers.

Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
THE THREE COSECUTIVE INTEGERS ARE X, X+1 & X+2.
(X+2)^2=(X+1)^2+76
X^2+4X+4=X^2+2X+1+76
4X-2X=-4+1+76
2X=73
X=73/2
X=36.5
X+1=37.5 ANSWER FOR THE SECOND NUMBER
X=2=38.5 ANSWER FOR THE THIRD NUMBER.
PROOF
(38.5^2=37.5^2+76
1482.25=1406.25+76
1482.25=1482.25
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