SOLUTION: The sum of the square of a positive number and the square of 3 more than the number is 29.can you show steps how to work this out and the correct answer ?
Algebra.Com
Question 1107916: The sum of the square of a positive number and the square of 3 more than the number is 29.can you show steps how to work this out and the correct answer ?
Found 2 solutions by JThomson, ikleyn:
Answer by JThomson(12) (Show Source): You can put this solution on YOUR website!
Let the number be 'x'
The square of the number is x^2
3 more than the number is (x+3);
The square of 3 more than the number is (x+3)^2
So x^2+(x+3)^2 = 29
x^2+(x^2+6x+9)-29=0
2x^2+6x-20=0
x^2+3x-10=0
(x+5)(x-2)=0
x=-5 and 2
But since x must be a positive number, x=2 .
Answer by ikleyn(52927) (Show Source): You can put this solution on YOUR website!
.
Let the number be 'x'
The square of the number is x^2
3 more than the number is (x+3);
The square of 3 more than the number is (x+3)^2
So x^2+(x+3)^2 = 29
x^2+(x^2+6x+9)-29=0
2x^2+6x-20=0
x^2+3x-10=0
(x+5)(x-2)=0
x=-5 and 2
But since x must be a positive number, x=2.
Answer. The number is 2.
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