SOLUTION: The difference between two times one number and a lesser one is 48. The sum of the greater number and three times the lesser number is 62. Find the numbers

Question 1101754: The difference between two times one number and a lesser one is 48. The sum of the greater number and three times the lesser number is 62. Find the numbers
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Two numbers, a & b(lessor)
:
The difference between two times one number and a lesser one is 48.
2a - b = 48
The sum of the greater number and three times the lesser number is 62.
a + 3b = 62
a = -3b + 62
:
Find the numbers
In the first equation, replace a with (-3b+62)
2(-3b + 62) - b = 48
-6b + 124 - b = 48
-7b = 48 - 124
-7b = -76
b = -76/-7
b = +76/7
or
b = +10
then
a = -3(76/7) + 62
a = -(228/7) + 62
a = -(228/7) + (434/7)
a = 206/7
a = 29
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