SOLUTION: Find three consecutive odd integers such that 3 times the 2nd is 1 less than the 1st and 3rd.

Question 1099120: Find three consecutive odd integers such that 3 times the 2nd is 1 less than the 1st and 3rd.
Found 2 solutions by josmiceli, ankor@dixie-net.com:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let the 3 consecvutive odd integers be
. , and
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and

and

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The consecutive odd integers are:
-3, -1 and 1
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check:

OK
get a 2nd opinion if needed

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Find three consecutive odd integers
n, (n+2), (n+4)
such that 3 times the 2nd is 1 less than the 1st and 3rd.
3(n+2) = n + (n+4) - 1
3n + 6 = 2n + 3
3n - 2n = 3 - 6
n = -3
:
The 3 consecutive odd integers: -3, -1, +1
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