SOLUTION: A person invested $5,200, part in bonds bearing 5.9% interest and the remainder in bonds bearing 7.6% interest. Both investments paid the same amount. How much, to the nearest doll

Question 1098926: A person invested $5,200, part in bonds bearing 5.9% interest and the remainder in bonds bearing 7.6% interest. Both investments paid the same amount. How much, to the nearest dollar, was invested in each?

Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
x+y=5200
x=5200-y
.059x=i
.076y=i
.059x=.076y
x/y=.076/.059=1.28813559322
x/y=1.28813559322
(5200-y)/y=1.28813559322
5200-y=1.28813559322y
5200=2.28813559322y
5200/2.28813559322=y
y=2272.59259259 to nearest dollar $2273 at 7.6%
x=5200-y
x=5200-2272.59259259=2927.40740741 to nearest dollar $2927 at 5.9%
.059*2927.40740741=172.717037037
.076*2272.59259259=172.717037037

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