SOLUTION: "One number exceeds by 8, and the sum of the smaller and twice the larger is 40. Find the product of the two numbers. The answer is supposedly 128 then, what could be the solution

Question 1097849: "One number exceeds by 8, and the sum of the smaller and twice the larger is 40. Find the product of the two numbers. The answer is supposedly 128 then, what could be the solution in arriving that answer?
Found 3 solutions by greenestamps, josgarithmetic, MathTherapy:
Answer by greenestamps(13215)   (Show Source): You can put this solution on YOUR website!

Thanks for trying again... but you have still left something out of your statement of the problem:

"One number exceeds by 8..."

Exceeds what?!

It is obvious what you mean, so I will go ahead and help you. But the polite thing for you to do would be to give us the whole problem so we don't have to try to figure out what is missing.

"one number exceeds ANOTHER by 8":
Let the smaller number be x; then the other is x+8.

"the sum of the smaller and twice the larger is 40":

I will assume you can finish from there....
Answer by josgarithmetic(39630)   (Show Source): You can put this solution on YOUR website!
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One number exceeds THE OTHER NUMBER by 8, and the sum of the smaller and twice the larger is 40. Find the product of the two numbers. The answer is supposedly 128 then
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Numbers, n and n+8.

-
The numbers are 8 and 16.

PRODUCT:

Answer by MathTherapy(10557)   (Show Source): You can put this solution on YOUR website!

"One number exceeds by 8, and the sum of the smaller and twice the larger is 40. Find the product of the two numbers. The answer is supposedly 128 then, what could be the solution in arriving that answer?

Smaller number: 8
Larger number: 16
Product of smaller and larger:
IGNORE ANYONE who says otherwise!
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