This is my problem: A two-digit counting number has a value that is 8 times the sum of its digits. If 6 times the units' digit is 5 more than the tens' digit, what is the number? My math book has not given me an example of this variation of kind of problem, and I can't find one on YouTube. Can you help me learn to solve this? Walk me through the different steps? Thank you for your time!
The only sentence you need in order to figure this out is this, "A two-digit counting number has a value that is 8 times the sum of its digits." Nothing else!!
Let the tens and units digits be T and U, respectively
Then the number is: 10T + U, and we get: 10T + U = 8(T + U)
10T + U = 8T + 8U
10T - 8T = 8U - U
2T = 7U <====== This means that T = 7, and U = 2, as these are the only 2 DIGITS that satisfy this equation.
Hence, the number is: . That's it!!