SOLUTION: The sum of two integers is 438, and the larger number is 14 more than 7 times the smaller number. Find the two integers
Algebra.Com
Question 1095959: The sum of two integers is 438, and the larger number is 14 more than 7 times the smaller number. Find the two integers
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The sum of two integers is 438,
a + b = 438
and the larger number is 14 more than 7 times the smaller number.
a = 7b + 14
In the first equation, replace a with (7b+14)
(7b+14) + b = 438
8b = 438 - 14
8b = 424
b = 424/8
b = 53
:
Find a
a =7(53) + 14
a = 371 + 14
a = 385
:
:
Check this, the sum: 385 + 53 = 438
RELATED QUESTIONS
The sum of two integers is 246 and the larger number is 27 more than 2 times the smaller... (answered by LearnWithMajor)
The sum of two integers is 368, and the larger number is 13 more than 4 times the smaller (answered by CubeyThePenguin)
The Sum of two integers in 174, and the larger number is 12 more than 2 times the smaller (answered by josgarithmetic)
the sum of two integers is 210, and the larger number is 24 more than 5 times the smaller (answered by vleith,janineannc)
The sum of two integers is 241 and the large number is 49 more than 5 times the smaller... (answered by josgarithmetic)
the sum of two odd integers is 11 times more than three times the larger number. find the (answered by macston)
the sum of two odd consecutive integers is 11 more than three times the larger number.... (answered by josgarithmetic)
The sum of two integers is 51. The larger number is 3 more than twice the smaller number. (answered by checkley77)
The Sum Of Two Consecutive Odd Integers Is 11 More Than Three Times The Larger... (answered by hamsanash1981@gmail.com)