SOLUTION: How many liters of 70% alcohol and 40% solution must be mixed to obtain 6 liters of 60% alcohol solution?

Question 1095387: How many liters of 70% alcohol and 40% solution must be mixed to obtain 6 liters of 60% alcohol solution?
Found 2 solutions by josgarithmetic, addingup:
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
x and y liters of 40% and 70%

--------equation in ONE variable
-

-
2 liters of 40% alcohol
4 liters of 70% alcohol
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
0.7x + 0.4(6 - x) = 0.6(6)
0.7x + 2.4 - 0.4x = 3.6
0.3x / 1.2
x = 4 you need 4 liters of the 70% solution and
6 - 4 = 2 liters of the 40% solution

RELATED QUESTIONS
How many liters of 70% alcohol solution and 40% alcohol solution must be mixed to obtain... (answered by josgarithmetic)
How many liters of 60% alcohol solution and 30% alcohol solution must be mixed to obtain... (answered by josmiceli,richwmiller)
How many liters of 20% alcohol and 75% alcohol must be mixed to obtain 32L of 40% alcohol (answered by stanbon)
How many liters of 60% alcohol solution and 30% alcohol solution must be mixed to obtain... (answered by sofiyac)
How many Liters of a 50% alcohol solution must be mixed with 40 Liters to obtain a 60... (answered by ptaylor)
How many liters of 80% alcohol solution and 20% alcohol solution must be mixed to obtain... (answered by checkley79)
How many liters of 60% alcohol solution and 20% alcohol solution must be mixed to obtain... (answered by richwmiller)
How many liters of 80% alcohol solution and 20% alcohol solution must be mixed to obtain... (answered by josmiceli)
how many liters of 60% alcohol solution and 40% alcohol solution should be mixed to... (answered by ptaylor)