SOLUTION: The square of the sum of two positive, consecutive, even numbers exceeds the sum of their squares by 336. Find the numbers.

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Question 1094072: The square of the sum of two positive, consecutive, even numbers exceeds the sum of their squares by 336. Find the numbers.

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Numbers x and x+2

%28x%2Bx%2B2%29%5E2-%28x%5E2%2B%28x%2B2%29%5E2%29=336

.
.
x%5E2%2B2x-168=0

%28x-12%29%28x%2B14%29=0

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system%28x=12%2C+and%2C+x%2B2=14%29
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-
%2812%2B14%29%5E2-%2812%5E2%2B14%5E2%29
26%5E2-%28144%2B196%29
26%5E2-340
676-340
336

Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
.
You are given

%28x%2By%29%5E2 - %28x%5E2%2By%5E2%29 = 336,    (1)

which is equivalent to

x%5E2+%2B+2xy+%2B+y%5E2+-+x%5E2+-+y%5E2 = 336,   or

2xy = 336,   or   xy = 336%2F2 = 168,


where x and y are integer numbers.


So, any pair of integers with xy = 168 is the solution to equation (1).


x     y

1     168
2      84
3      56
4      42
6      28
8      21
12     14


and all reverted pairs,  and all the pairs with opposite numbers.


Of them, only the pair  (12,14)  represents  consecutive positive even integers.