SOLUTION: The number of bacteria present in a culture after t minutes is given as B=10e^kt. If they are 593 bacteria present after nine minutes, find k
Take logarithms of both sides,... and solve for k. Use Natural Logarithm.
You finish the steps.
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. Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website! The number of bacteria present in a culture after t minutes is given as B=10e^kt. If they are 593 bacteria present after nine minutes, find k
------ Substituting 593 for B, and 9 for t ------- Dividing each side by 10 ------ Converting to LOGARITHMIC (natural) form
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