SOLUTION: The sum of three numbers is 91 the first number is nine more than the second the third number is two times the first what are the numbers
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Question 1076464: The sum of three numbers is 91 the first number is nine more than the second the third number is two times the first what are the numbers
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The sum of three numbers is 9
a + b + c = 91
the first number is nine more than the second
a = b + 9
or
b = a - 9
the third number is two times the first
c = 2a
what are the numbers
Using the first equation, replace b with (a - 9); replace c with 2a
a + (a-9) + 2a = 91
4a = 91 + 9
4a = 100
a = 25 is the first number
then
b = 25 - 9
b = 16 is the 2nd number
and
c = 2(25)
c = 50 is the 3rd number
:
:
See if that checks out
25 + 16 + 50 = 91
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