SOLUTION: If 2 times a number is decreased by 6​, the principal square root of this difference is 7  less than the number. Find the​ number(s).
Algebra.Com
Question 1065648: If 2 times a number is decreased by 6, the principal square root of this difference is 7 less than the number. Find the number(s).
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
number is x
2x-6 is the number whose square root is x-7
square both sides
2x-6=(x-7)^2=x^2-14x+49
0=x^2-16x+55
0=(x-11)(x-5)
x=11 or 5
if 11, square root of 16 is 4, 7 fewer than 11.
if 5, square root of 4 is 2, and that is not 7 fewer than 5, and that is the principal square root.
11 is the number.
RELATED QUESTIONS
If 22 times a number is decreased by 55, the principal square root of this... (answered by josgarithmetic,greenestamps)
If 2 times a number is decreased by 9, the principal square root of this difference is 6... (answered by ankor@dixie-net.com)
A game is played using one die. If the die is rolled and shows 4, the player wins (answered by stanbon)
When 4 is added to the difference between nine times a number... (answered by macston)
If 5 times a number is decreased by 4 the principal root of this difference is 2 less... (answered by kevwill)
The sum of two numbers is 118.
If three times
the smaller number is... (answered by addingup,solver91311)
If a number is subtracted from 43,the principal square root of this difference is equal... (answered by MathLover1,ikleyn,josmiceli)
Use long division to find the quotient Q(x) and the remainder R(x)... (answered by Fombitz)
A die is rolled
12
times. Find the probability of rolling exactly... (answered by Alan3354)