SOLUTION: The hundreds digit of a 3-digit number is 2 less than the tens digit, and the ones digit is 2 less than the hundreds digit. If twice the sum of the digits decreased by 10 is 20, w

Question 1062851: The hundreds digit of a 3-digit number is 2 less than the tens digit, and the ones digit is 2 less than the hundreds digit. If twice the sum of the digits decreased by 10 is 20, what is the number?
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
Let n be the tens digit of the number. Then the hundred digit is n-2, and the ones digit is n-2-2, or n-4. So:
2(n+n-2+n-4)-10=20
6n-22=20
6n=42
n=7
n-2=5
n-4=3
So the number is 573. ☺☺☺☺
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