SOLUTION: I am a 4-digit number. My first digit is a cube. My second digit is prime. My second, third, and fourth digit are consecutive even numbers. My third digit is a square and my

Question 1062372: I am a 4-digit number. My first digit is a cube. My second
digit is prime. My second, third, and fourth digit are
consecutive even numbers. My third digit is a square and my
last digit is thrice my second digit.

Found 2 solutions by Edwin McCravy, MathTherapy:
Answer by Edwin McCravy(20060) (Show Source): You can put this solution on YOUR website!
I am a 4 digit number.

Let X's represent the digits: XXXX

My second, third,fourth digit are consecutive even numbers,

So it's either X024 or X246 or X468

My third number is a square.

So it can only be X246

My first digit is a cube.

The only digits that are cubes are 1 and 8. That's because 1³=1 and 2³=8 So it either 1246 or 8246

My second digit is prime.

We don't need that information because 2 is prime.

my last digit is thrice my second digit.

We don't need that information either because 6 is thrice 2. But we still can't tell whether it's 1246 or 8246. Edwin

Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!
I am a 4-digit number. My first digit is a cube. My second
digit is prime. My second, third, and fourth digit are
consecutive even numbers. My third digit is a square and my
last digit is thrice my second digit.

1^st Digit: Only 2 digits are cubes: 1 and 8, so this can be either.
2^nd Digit: With this being PRIME and EVEN, this MUST be 2
3^rd and 4^th Digits: 4 and 6
Number: 1,246, or 8,246
Clues in first 2 sentences were enough to determine numbers.
This 3rd sentence was UNNECESSARY: My third digit is a square and my last digit is thrice my second digit.
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