SOLUTION: Find three consecutive odd integers such that the largest increased by three times the second is 47 less than the smallest.

Question 106202: Find three consecutive odd integers such that the largest increased by three times the second is 47 less than the smallest.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Just write equation for what it says:
:
"Find three consecutive odd integers"
x, x+2, x+4
:
"the largest increased by three times the second is 47 less than the smallest."
(x+4) + 3(x+2) = x - 47
x + 4 + 3x + 6 = x - 47
4x + 10 = x - 47
4x -x = -47 - 10
3x = - 57
x = -57/3
x = -19
:
Our three odd integers: -19, -17, -15:
:
Check solution in the statement,:
"the largest increased by three times the second is 47 less than the smallest."
-15 + 3(-17) = -19 - 47
-15 - 51 = -19 - 47

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