SOLUTION: Find two consecutive integers such that one-half of the larger exceeds one-third of the smaller by 9.

Question 1055377: Find two consecutive integers such that one-half of the larger exceeds one-third of the smaller by 9.
Answer by ikleyn(52793) (Show Source): You can put this solution on YOUR website!
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Find two consecutive integers such that one-half of the larger exceeds one-third of the smaller by 9.
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 = 9,

Multiply by 6 both sides.

3(n+1) - 2n = 54,

3n + 3 - 2n = 54,

n = 54 - 3 = 51.

Answer.  51 and 52.

Check.    = 26 - 17 = 9.  Correct!

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