SOLUTION: Divide the number 43 in two parts . such that 5times the smaller part is a less than thrice the larger part

Question 1055016: Divide the number 43 in two parts . such that 5times the smaller part is a less than thrice the larger part

Found 2 solutions by addingup, MathTherapy:
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
5x < 3y; x < 3/5y we'll use this value for x below.
----------------------
5(3/5y)+3y < 43
15/5y+3y < 43
3y+3y < 43
6y < 43
y < 43/6
y < 7.116
y = 7 and x= 6
7*6 = 42
and
42 < 43

Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!
Divide the number 43 in two parts . such that 5times the smaller part is a less than thrice the larger part

Therefore, if smaller part = 16, then larger part = 43 - 16, or 27
If smaller part = 15, then larger part = 43 - 15, or 28, and SO FORTH!
FYI: Other person's attempt at solving makes ABSOLUTELY NO SENSE!
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