SOLUTION: The larger of two numbers is 9 less than eight times the smaller. When the smaller number is subtracted from the larger, the difference is 13. Find the two numbers.

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Question 1054076: The larger of two numbers is 9 less than eight times the smaller. When the smaller number is subtracted from the larger, the difference is 13. Find the two numbers.
Answer by jorel555(1290)   (Show Source): You can put this solution on YOUR website!
Let m and n be your two numbers. Then:
m=8n-9
m-n=13
So:
m=8(m-13)-9
m=8m-113
113=7m
m=16 and 1/7th
n=3 and 1/7th. ☺☺☺☺

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