SOLUTION: I am a two digit no.my tens digit is a multiple of my ones digit.the sum of my digit is nine.and the no is

Question 1051433: I am a two digit no.my tens digit is a multiple of my ones digit.the sum of my digit is nine.and the no is
Found 2 solutions by ankor@dixie-net.com, advanced_Learner:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A five digit-number:
A B C D E
:
the first two digits are the same;
A A C D E
:
the sum of the two digits equals the two-digit number formed by reading the third and fourth digits together;
2A = 10C + D
From this we know that C = 1, and D is an even number
:
the last digit is the sum of the third and fourth digits,
E = C + D
E = D + 1
:
and is also one half of the first digit.
A = E
A = 2E
we know E = D+1, and C = 1 therefore
A = 2(D+1)
Now our number
2(D+1), 2(D+1), 1, D, (D+1)
We know the D is even, A < 10, so D=2
6, 6 , 1, 2, 3
:
what is the number? 66123, note the sum of the 1st two digits = 12
Answer by advanced_Learner(501) (Show Source): You can put this solution on YOUR website!
63

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